On a line

On a line p : 3 x - 4 y - 3 = 0, determine the point C equidistant from points A[4, 4] and B[7, 1].

Correct result:

x =  9
y =  6

Solution:

3x4y3=0  x=(3+4y)/3=9 y=(3x3)/4 AC=BC  (x4)2+(y4)2=(x7)2+(y1)2  (x4)2+((3x3)/44)2=(x7)2+((3x3)/41)2 1.5x=13.5 32x=272 3x=27 x=27/3=9 
y=(3x3)/4=(3 93)/4=6



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