Lengths of medians from coordinates

There is a triangle ABC: A [-6.6; 1.2], B [3.4; -5.6], C [2.8; 4.2]. Calculate the lengths of its medians.

t₁ = 9.8843
t₂ = 9.8478
t₃ = 7.7666

A = (- 6.6, 1.2) = (- 6.6, 1.2) B = (3.4, - 5.6) = (3.4, - 5.6) C = (2.8, 4.2) = (2.8, 4.2) T_{x} = \frac{A _{x} + B _{x} + C _{x}}{3} = \frac{( - 6 . 6 ) + 3 . 4 + 2 . 8}{3} = - \frac{2}{1 5} ≐ - 0.1333 T_{y} = \frac{A _{y} + B _{y} + C _{y}}{3} = \frac{1 . 2 + ( - 5 . 6 ) + 4 . 2}{3} = - \frac{1}{1 5} ≐ - 0.0667 \frac{A T}{T X} = 2 : 1 t_{1} = ∣ A T ∣ + ∣ T X ∣ A T = (T_{x} - A_{x})^{2} + (T_{y} - A_{y})^{2} = ((- 0.1333) - (- 6.6))^{2} + ((- 0.0667) - 1.2)^{2} ≐ 6.5896 t_{1} = \frac{3}{2} \cdot A T = \frac{3}{2} \cdot 6.5896 = 9.8843

B T = (T_{x} - B_{x})^{2} + (T_{y} - B_{y})^{2} = ((- 0.1333) - 3.4)^{2} + ((- 0.0667) - (- 5.6))^{2} ≐ 6.5652 t_{2} = \frac{3}{2} \cdot B T = \frac{3}{2} \cdot 6.5652 = 9.8478

C T = (T_{x} - C_{x})^{2} + (T_{y} - C_{y})^{2} = ((- 0.1333) - 2.8)^{2} + ((- 0.0667) - 4.2)^{2} ≐ 5.1777 t_{3} = \frac{3}{2} \cdot C T = \frac{3}{2} \cdot 5.1777 = 7.7666

Try calculation via our triangle calculator.

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Tips for related online calculators

Looking for help with calculating arithmetic mean?
Looking for a statistical calculator?
Check out our ratio calculator.
Our vector sum calculator can add two vectors given by their magnitudes and by included angle.
See also our right triangle calculator.
See also our trigonometric triangle calculator.