Cooling liquid

Cooling liquid is diluted with water in a ratio of 3:2 (3 parts by volume of coolant with 2 volumes of water). How many volumes of coolant must be prepared for a total 0.7 dm3 (liters) of the mixture?

Result

x =  0.42 l

Solution:

d=0.7/(3+2)=750=0.14 l x=3 d=3 0.14=2150=0.42=0.42  l d = 0.7 / (3+2) = \dfrac{ 7 }{ 50 } = 0.14 \ l \ \\ x = 3 \cdot \ d = 3 \cdot \ 0.14 = \dfrac{ 21 }{ 50 } = 0.42 = 0.42 \ \text{ l }



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