# Liter of gold

What weight does 1 dm3 of gold have? Gold density is 19,300 kg / m3

Result

m =  19.3 kg

#### Solution:

$V=1 \ \text{dm}^3 \ \\ h=19300/10^3=\dfrac{ 193 }{ 10 }=19.3 \ \text{kg/dm}^3 \ \\ m=V \cdot \ h=1 \cdot \ 19.3=\dfrac{ 193 }{ 10 }=19.3 \ \text{kg}$

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