Alcohol mixture

Three liters of 96 percent alcohol set up a certain amount of distilled water to form 54 percent alcohol. How many liters of distilled water were used?

Final Answer:

x =  2.3333 l

Step-by-step explanation:

c1=96%=10096=2524=0.96 c2=54%=10054=5027=0.54 V1=3 l  V1 c1=c2 (V1+x) 3 0.96=0.54 (3+x)  0.54x=1.26  x=0.541.26=2.33333333  x=372.333333=2.3333 l



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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsUnits of physical quantitiesthemes, topicsGrade of the word problem

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