Alcohol 2

Two types of alcohol one 63% and second 75% give 20 liters of 69% alcohol. How many liters of each type are in the mixture?

Result

A =  10
B =  10

Solution:

A+B = 20
A*(63/100)+B*(75/100)=20*(69/100)

A+B = 20
63A+75B = 1380

A = 10
B = 10

Calculated by our linear equations calculator.

Leave us a comment of this math problem and its solution (i.e. if it is still somewhat unclear...): Nestor
Your solution did not use the "given" in the problem i.e., instead of 70%< you used 69%. Dr Math
Fixed this typo problem, thank you! To solve this verbal math problem are needed these knowledge from mathematics:

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