Alcohol 2

Two types of alcohol one 63% and second 75% give 20 liters of 69% alcohol. How many liters of each type are in the mixture?

Correct result:

A =  10
B =  10

Solution:


A+B = 20
A•(63/100)+B•(75/100)=20•(69/100)

A+B = 20
63A+75B = 1380

A = 10
B = 10

Our linear equations calculator calculates it.



We would be pleased if you find an error in the word problem, spelling mistakes, or inaccuracies and send it to us. Thank you!






Showing 2 comments:
#
Nestor
Your solution did not use the "given" in the problem i.e., instead of 70%< you used 69%.

#
Dr Math
Fixed this typo problem, thank you!

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