Solution

In 201 l, the red solution is 143 l in red color, and in 227 l, the blue solution is 112 l in blue color. How many l of red and blue l color solution must be mixed to get a mixture of 242 l to contain 121 l of color?

Final Answer:

x =  7.3 l
y =  234.7 l

Step-by-step explanation:

$$\begin{gathered} r_1=143/201=\frac{143}{201}\doteq 0.7114 \\ {r}_2=112/227=\frac{112}{227}\doteq 0.4934 \\ x+y=242 \\ {r}_1\cdot x+r_2\cdot y=121 \\ x+y=242 \\ 0.71144278606965\cdot x+0.49339207048458\cdot y=121 \\ x+y=242 \\ 0.711443x+0.493392y=121 \\ Row2-0.71144278606965\cdot Row1\to Row2 \\ -0.22y=-51.17 \\ y=\frac{-51.16915423}{-0.21805072}=234.66629812 \\ x=242-y=242-234.66629812=7.33370188=7.3\text{l} \\ x=7.333702 \\ y=234.666298 \end{gathered}$$

$y==234.7\text{l}$

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