# Container

The container has a cylindrical shape the base diameter 0.8 m and the area of the base is equal to the area of the wall. How many liters of water can we pour into the container?

Correct result:

V =  100.531 l

#### Solution:

$D=0.8 \ \text{m} \ \\ r=D/2=0.8/2=\dfrac{ 2 }{ 5 }=0.4 \ \text{m} \ \\ S=\pi \cdot \ r^2=3.1416 \cdot \ 0.4^2 \doteq 0.5027 \ \text{m}^2 \ \\ S=\pi \cdot \ D \cdot \ h \ \\ h=S/(\pi \cdot \ D)=0.5027/(3.1416 \cdot \ 0.8)=\dfrac{ 1 }{ 5 }=0.2 \ \text{m} \ \\ V_{1}=S \cdot \ h=0.5027 \cdot \ 0.2 \doteq 0.1005 \ \text{m}^3 \ \\ V=1000 \cdot \ V_{1}=1000 \cdot \ 0.1005=100.531 \ \text{l}$

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