The projectile

The projectile leaves the 10 m long barrel at an instantaneous speed of 500 m/s. What is the acceleration of the movement of the projectile in the barrel and in what time will the projectile pass the barrel if, we assume that the movement was evenly accelerated?

Correct answer:

a =  12500 m/s2

Step-by-step explanation:

s=10 m v=500 m/s  v=a t s=21 a t2 s=21 a (v/a)2 s=21 v2/a  a=2 sv2=2 105002=12500=12500 m/s2  SK  t=v/a=500/12500=251=0.04 s s2=21 a t2=21 12500 0.042=10 m s2=s

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