The tram

The tram is moving with acceleration a = 0.3m/s2. How long it will pass the first meter of track? How long does it take 10 meters. What is its speed at the end of the 10 meters track?

Correct result:

t₁ =  2.582 s
t₂ =  8.165 s
v₂ =  2.4495 m/s

Solution:

$$\begin{gathered} a=0.3 \\ {s}_1=1 \\ {t}_1=\sqrt{2\cdot s_1\mathrm{/}a}=\sqrt{2\cdot 1\mathrm{/}0.3}=2.582\text{ s} \end{gathered}$$

$$\begin{gathered} s_2=10 \\ {t}_2=\sqrt{2\cdot s_2\mathrm{/}a}=\sqrt{2\cdot 10\mathrm{/}0.3}=8.165\text{ s} \end{gathered}$$

$v_2=a\cdot t_2=0.3\cdot 8.165=\sqrt{6}=2.4495\text{ m/s}$

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