The tram

The tram is moving with acceleration a = 0.3m/s2. How long it will pass the first meter of track? How long does it take 10 meters. What is its speed at the end of the 10 meters track?

Result

t1 =  2.582 s
t2 =  8.165 s
v2 =  2.45 m/s

Solution:

a=0.3 s1=1 t1=2⋅ s1/a=2⋅ 1/0.3≐2.582≐2.582 sa=0.3 \ \\ s_{1}=1 \ \\ t_{1}=\sqrt{ 2 \cdot \ s_{1}/a }=\sqrt{ 2 \cdot \ 1/0.3 } \doteq 2.582 \doteq 2.582 \ \text{s}
s2=10 t2=2⋅ s2/a=2⋅ 10/0.3≐8.165≐8.165 ss_{2}=10 \ \\ t_{2}=\sqrt{ 2 \cdot \ s_{2}/a }=\sqrt{ 2 \cdot \ 10/0.3 } \doteq 8.165 \doteq 8.165 \ \text{s}
v2=a⋅ t2=0.3⋅ 8.165=2.4495=2.45 m/sv_{2}=a \cdot \ t_{2}=0.3 \cdot \ 8.165=2.4495=2.45 \ \text{m/s}

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