Simultaneously 4372

From two places, M and N, 100 m apart, two bodies move simultaneously in the positive direction of the x-axis. A body moving from place M has a speed of 5 m/s, from place N 3 m/s. How long does it take for the first body to catch up with the second? What path will the bodies travel in this time?

Correct answer:

t =  50 s
s₁ =  150 m
s₂ =  250 m

Step-by-step explanation:

s = 100+3t
s=5t

s = 100+3·t
s=5·t

s-3t = 100
s-5t = 0

Row 2 - Row 1 → Row 2
s-3t = 100
-2t = -100


t = -100/-2 = 50
s = 100+3t = 100+3 · 50 = 250

s = 250
t = 50

Our linear equations calculator calculates it.

$s_1=3\cdot t=3\cdot 50=150\text{m}$

$s_2=5\cdot t=5\cdot 50=250\text{m}$

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