Deceleration of car

The car has a speed of 60 km/h and after 100 m journey speed of 40 km/h. What is the deceleration of a car if we assume that its movement is constantly slowed down?

Correct result:

a =  0.7716 m/s2

Solution:

v1=60 km/h m/s=60/3.6  m/s=16.66667 m/s s=100 m v2=40 km/h m/s=40/3.6  m/s=11.11111 m/s  s=v1 t12 a t2  a=v1v2t=0.7716 m/s2   s=v1 t0.5 (v1v2)/t t2    s=v1 t0.5 (v1v2) t 100=16.6666666667 t0.5 (16.666666666711.1111111111) t  13.888889t=100  t=3657.2  a=v1v2t=16.666711.11117.2=1251620.7716   Verifying Solution:   s1=v1 t12 a t2=16.6667 7.212 0.7716 7.22=100 m s=s1 v3=v1a t=16.66670.7716 7.2=100911.1111 m/s v3=v2



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