Scrap

From 6 products are 3 scrap. What is the probability that the random pick of 2 products have no defective product?

Result

p =  0.2

Solution:

p=63663161=0.2p= \dfrac{ 6-3 }{ 6} \cdot \dfrac{ 6-3-1}{ 6-1} = 0.2



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