Diagonal to area

Calculate the area of a rectangle in which the length of the diagonal is 10 cm.

Correct result:

S =  36.661 cm2

Solution:

u=10 cm a=4 cm b=u2−a2=102−42≐2 21 cm≐9.1652 cm  S=a⋅ b=4⋅ 9.1652=8 21=36.661 cm2u=10 \ \text{cm} \ \\ a=4 \ \text{cm} \ \\ b=\sqrt{ u^2-a^2 }=\sqrt{ 10^2-4^2 } \doteq 2 \ \sqrt{ 21 } \ \text{cm} \doteq 9.1652 \ \text{cm} \ \\ \ \\ S=a \cdot \ b=4 \cdot \ 9.1652=8 \ \sqrt{ 21 }=36.661 \ \text{cm}^2

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