The bulbs

The bulbs are connected serially two bulbs and one resistor. Each bulb has a resistivity of 100 ohms and resistor of 60 ohms
The voltage source in the circuit is 24 volts.

Do you know what voltage to measure on individual appliances?

Correct result:

U1 =  9.231 V
U2 =  9.231 V
U3 =  5.538 V

Solution:

U=24 V R1=100 Ω R2=100 Ω R3=60 Ω  R=R1+R2+R3=100+100+60=260 Ω I=U/R=24/2606650.0923 A  U1=R1 I=100 0.0923=12013=9.231 VU=24 \ \text{V} \ \\ R_{1}=100 \ Ω \ \\ R_{2}=100 \ Ω \ \\ R_{3}=60 \ Ω \ \\ \ \\ R=R_{1}+R_{2}+R_{3}=100+100+60=260 \ Ω \ \\ I=U/R=24/260 \doteq \dfrac{ 6 }{ 65 } \doteq 0.0923 \ \text{A} \ \\ \ \\ U_{1}=R_{1} \cdot \ I=100 \cdot \ 0.0923=\dfrac{ 120 }{ 13 }=9.231 \ \text{V}
U2=R2 I=100 0.0923=12013=9.231 VU_{2}=R_{2} \cdot \ I=100 \cdot \ 0.0923=\dfrac{ 120 }{ 13 }=9.231 \ \text{V}
U3=R3 I=60 0.0923=7213=5.538 VU_{3}=R_{3} \cdot \ I=60 \cdot \ 0.0923=\dfrac{ 72 }{ 13 }=5.538 \ \text{V}



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