Two-digit 6212

I think of a number, add it to itself, subtract 6, then divide by 2, add 7 and multiply by 8. The largest two-digit number that contains only even digits came out. How much is the result greater than the imaginary number?

Correct answer:

x =  7
y =  81

Step-by-step explanation:


((x+x-6)/2+7)·8=88

16x = 112


x = 112/16 = 7

x = 7

Our simple equation calculator calculates it.
y=88x=887=81



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