Rhombus ABCD

Rhombus ABCD, |AC| = 90 cm, |BD| = 49 cm.

Calculate the perimeter of the rhombus ABCD.

Correct answer:

p =  204.9 cm

Step-by-step explanation:

$p=4\cdot \sqrt{{\left({\displaystyle \frac{90}{2}}\right)}^2+{\left({\displaystyle \frac{49}{2}}\right)}^2}=204.9\text{ cm}$

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