Rhombus ABCD

Rhombus ABCD, |AC| = 90 cm, |BD| = 49 cm.

Calculate the perimeter of the rhombus ABCD.

Result

p =  204.9 cm

Solution:

p=4⋅(902)2+(492)2=204.9 cmp = 4\cdot \sqrt{ \left(\dfrac{ 90}{2} \right)^2+ \left( \dfrac{ 49}{2} \right)^2 } = 204.9 \ \text{cm}

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