Four-member team

There are 14 girls and 11 boys in the class. How many ways can a four-member team be chosen so that there are exactly two boys in it?

Correct answer:

n =  5005

Step-by-step explanation:

$n={\displaystyle \frac{(14\cdot 13)\cdot (11\cdot 10)}{2\cdot 2}}=5005$

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