Percentage 63864

Through the first pipe, 90 hl of water flows into the tank per hour, and 2.7 l of water per second through the second pipe. Calculate by what percentage more or less water flows per unit time into the tank through the second pipe than through the first pipe.

Correct answer:

p₁ =  8 %
p₂ =  7.4074 %

Step-by-step explanation:

$$\begin{gathered} Q_1=90\cdot 100/60=150\text{l/min} \\ {Q}_2=2.7\cdot 60=162\text{l/min} \\ {Q}_2>Q_1 \\ {p}_1=100\cdot \frac{Q_2-Q_1}{Q_1}=100\cdot \frac{162-150}{150}=8\% \end{gathered}$$

$p_2=100\cdot \frac{Q_2-Q_1}{Q_2}=100\cdot \frac{162-150}{162}=\frac{200}{27}\%=7.4074\%$

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