From the cube of edge 37 cm was lathed maximum cylinder. What percentage of the cube is left as waste after lathed?

Correct result:

p =  21.5 %


p=100%V1V2V1=100%373π372437373=100(1π4)=21.5%p = 100\% \cdot \dfrac{ V_1-V_2}{ V_1} = 100\% \cdot \dfrac{ 37^3-\pi \dfrac{ 37^2}{4} \cdot 37 }{ 37^3} = 100 \cdot (1- \dfrac{ \pi}{4} ) = 21.5 \%

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