Lathe

From the cube of edge 37 cm was lathed maximum cylinder. What percentage of the cube is left as waste after lathed?

Result

p =  21.5 %

Solution:

$p = 100\% \cdot \dfrac{ V_1-V_2}{ V_1} = 100\% \cdot \dfrac{ 37^3-\pi \dfrac{ 37^2}{4} \cdot 37 }{ 37^3} = 100 \cdot (1- \dfrac{ \pi}{4} ) = 21.5 \%$

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