# The tourist

The tourist came started from the hostel at an average speed of 5km/h. Half an hour later, the bicyclist started along the same route at a speed of 20km/h. How many minutes will a cyclist catch up and how many kilometers will he go?

Result

t =  10 min
s =  3.333 km

#### Solution:

$\ \\ 5 \cdot \ (t/60+ 30/60)=s \ \\ s=20 \cdot \ t/60 \ \\ \ \\ 60s-5t=150 \ \\ 60s-20t=0 \ \\ \ \\ s=\dfrac{ 10 }{ 3 } \doteq 3.333333 \ \\ t=10 \ \\ =10 \ \text{min}$
$s=3.3333=\dfrac{ 10 }{ 3 } \doteq 3.3333 \doteq 3.333 \ \text{km}$

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