# Rope

One half of rope use Mam for packaging, half of the rest got son, half of the rest he took father and two fifths of what remained, got daughter. Remained 143 cm of rope.

How long was rope at the beginning?

Result

x =  1907

#### Solution:

$(1- \dfrac25)\cdot (1-\dfrac12)\cdot (1-\dfrac12)\cdot (1-\dfrac12) \cdot x = 143 \ \\ \dfrac35\cdot \dfrac12\cdot \dfrac12\cdot \dfrac12 \cdot x = 143 \ \\ x=1907$

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