Opposite direction - walkers

Father Eduard from place A and son Jaroslav from place B set out at the same time towards each other. The faster one is the father and the slower one the son. They meet at 12 o'clock and continue further along the route of their "opposite walker". The faster father reaches the opposite place B at 4 p.m. The slower son only at 4 a.m. the following day. We are not asking how fast they walked, nor at what speed, but when they set off together on this journey.

Result

t = 4:00 hh:mm Wrong answer

Step-by-step explanation:

a(12t)+b(12t) = s s = a(16t) s = b(24+4t) a=1 b=1/2=21=0.5 s=12 t=4=4:00 hh:mm



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