Consecutive number middle

There are five consecutive natural numbers. If the middle number is subtracted from the sum of the other four, I get 21. Specify these numbers.

Final Answer:

a =  5
b =  6
c =  7
d =  8
e =  9

Step-by-step explanation:

$$\begin{gathered} a+(a+1)+(a+3)+(a+4)-(a+2)=21 \\ 3a=15 \\ a=\frac{15}{3}=5 \\ a=5 \end{gathered}$$

$b=a+1=5+1=6$

$c=b+1=6+1=7$

$d=c+1=7+1=8$

$e=d+1=8+1=9$

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