Cube walls

Find the volume and the surface area of the cube if the area of one of its walls is 40 cm2.

Result

V =  252.982 cm3
S =  240 cm2

Solution:

S1=40 cm2 a=S1=402 10 cm6.3246 cm  V=a3=6.3246380 10252.9822252.982 cm3S_{1}=40 \ \text{cm}^2 \ \\ a=\sqrt{ S_{1} }=\sqrt{ 40 } \doteq 2 \ \sqrt{ 10 } \ \text{cm} \doteq 6.3246 \ \text{cm} \ \\ \ \\ V=a^3=6.3246^3 \doteq 80 \ \sqrt{ 10 } \doteq 252.9822 \doteq 252.982 \ \text{cm}^3
S=6 S1=6 40=240 cm2S=6 \cdot \ S_{1}=6 \cdot \ 40=240 \ \text{cm}^2



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