# Cube walls

Find the volume and the surface area of the cube if the area of one of its walls is 40 cm2.

Result

V =  252.982 cm3
S =  240 cm2

#### Solution:

$S_{1}=40 \ \text{cm}^2 \ \\ a=\sqrt{ S_{1} }=\sqrt{ 40 } \doteq 2 \ \sqrt{ 10 } \ \text{cm} \doteq 6.3246 \ \text{cm} \ \\ \ \\ V=a^3=6.3246^3 \doteq 80 \ \sqrt{ 10 } \doteq 252.9822 \doteq 252.982 \ \text{cm}^3$
$S=6 \cdot \ S_{1}=6 \cdot \ 40=240 \ \text{cm}^2$

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