Peaches

There are 20 peaches in the pocket. 3 peaches are rotten. What is the probability that one of the randomly picked two peaches will be just one rotten?

Correct answer:

p =  0.0671

Step-by-step explanation:

$p={\displaystyle \frac{3}{20}}\cdot {\displaystyle \frac{20-3}{20-1}}\mathrm{/}2={\displaystyle \frac{51}{760}}=0.0671$

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