Peaches

There are 20 peaches in the pocket. 3 peaches are rotten. What is the probability that one of the randomly picked two peaches will be just one rotten?

Correct result:

p =  0.067

Solution:

p=320⋅ 20−320−1/2=51760=0.067p=\dfrac{ 3 }{ 20 } \cdot \ \dfrac{ 20-3 }{ 20-1 } /2=\dfrac{ 51 }{ 760 }=0.067

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