Peaches

There are 20 peaches in the pocket. 3 peaches are rotten. What is the probability that one of the randomly picked two peaches will be just one rotten?

Result

p =  0.067

Solution:

p=320 203201/2=517600.0671=0.067p = \dfrac{ 3 }{ 20 } \cdot \ \dfrac{ 20-3 }{ 20-1 } /2 = \dfrac{ 51 }{ 760 } \doteq 0.0671 = 0.067



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