Peaches

There are 20 peaches in the pocket. 3 peaches are rotten. What is the probability that one of the randomly picked two peaches will be just one rotten?

Correct answer:

p =  0.2684

Step-by-step explanation:

$$\begin{gathered} C_2(20)=\left({\displaystyle \genfrac{}{}{0px}{}{20}{2}}\right)={\displaystyle \frac{20!}{2!(20-2)!}}={\displaystyle \frac{20\cdot 19}{2\cdot 1}}=190 \\ n=20 \\ a=3\cdot (n-3)=3\cdot (20-3)=51 \\ b=\left(\genfrac{}{}{0px}{}{n}{2}\right)=190 \\ p=a\mathrm{/}b=51\mathrm{/}190=0.2684 \end{gathered}$$

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