# Classroom

Of the 26 pupils in the classroom, 12 boys and 14 girls, four representatives are picked to the odds of being:
a) all the girls
b) three girls and one boy
c) there will be at least two boys

Correct result:

p1 =  0.067
p2 =  0.2922
p3 =  0.6409

#### Solution:

$p_{1}=\dfrac{ 14 \cdot \ 13 \cdot \ 12 \cdot \ 11 }{ 26 \cdot \ 25 \cdot \ 24 \cdot \ 23 }=\dfrac{ 77 }{ 1150 }=0.067$
${p}_{3}=1-{p}_{1}-{p}_{2}=1-0.067-0.2922=\frac{737}{1150}=0.6409$ We would be pleased if you find an error in the word problem, spelling mistakes, or inaccuracies and send it to us. Thank you! Tips to related online calculators
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