A book

A book contains 524 pages. If it is known that a person will select any one page between the pages numbered 125 and 384, find the probability of choosing the page numbered 252 or 253.

Result

p =  0.769 %

Solution:

C1(260)=(2601)=260!1!(2601)!=2601=260 C1(2)=(21)=2!1!(21)!=21=2  p=100 (21)(384125+11)=100 2(384125+11)10130.76920.769%C_{{ 1}}(260) = \dbinom{ 260}{ 1} = \dfrac{ 260! }{ 1!(260-1)!} = \dfrac{ 260 } { 1 } = 260 \ \\ C_{{ 1}}(2)=\dbinom{ 2}{ 1}=\dfrac{ 2! }{ 1!(2-1)!}=\dfrac{ 2 } { 1 }=2 \ \\ \ \\ p=100 \cdot \ \dfrac{ { { 2 } \choose 1 } }{ { { 384-125+1 } \choose 1 } }=100 \cdot \ \dfrac{ 2 }{ { { 384-125+1 } \choose 1 } } \doteq \dfrac{ 10 }{ 13 } \doteq 0.7692 \doteq 0.769 \%



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