Irrigation sprinkler

The irrigation sprinkler can twist with an angle of 320° and has a reach of 12 meters. Which area can irrigate?

Result

S =  402.1 m2

Solution:

A=320 ∘ r=12 m  S1=π⋅ r2=3.1416⋅ 122≐452.3893 m2 S=A360⋅ S1=320360⋅ 452.3893≐402.1239≐402.1 m2A=320 \ ^\circ \ \\ r=12 \ \text{m} \ \\ \ \\ S_{1}=\pi \cdot \ r ^2=3.1416 \cdot \ 12 ^2 \doteq 452.3893 \ \text{m}^2 \ \\ S=\dfrac{ A }{ 360 } \cdot \ S_{1}=\dfrac{ 320 }{ 360 } \cdot \ 452.3893 \doteq 402.1239 \doteq 402.1 \ \text{m}^2

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