Irrigation sprinkler

The irrigation sprinkler can twist with an angle of 320° and has a reach of 12 meters. Which area can irrigate?

Correct result:

S =  402.1 m2

Solution:

A=320∘ r=12 m  S1=π⋅ r2=3.1416⋅ 122≐452.3893 m2 S=A360⋅ S1=320360⋅ 452.3893=402.1 m2

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