Diagonals 7029

The number of diagonals of a given polygon is 88 more than the number of its sides. How many sides does this polygon have

Correct answer:

n =  16

Step-by-step explanation:

n(n3)/2=88+n  0.5n22.5n88=0  a=0.5;b=2.5;c=88 D=b24ac=2.5240.5(88)=182.25 D>0  n1,2=2ab±D=12.5±182.25 n1,2=2.5±13.5 n1=16 n2=11  n>0 n=n1=16

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