Polygon 42

Which polygon has 42 more diagonals than sides?

Final Answer:

n =  12

Step-by-step explanation:

 21n(n3)=n+42  n23n=2n+84  n25n84=0  a=1;b=5;c=84 D=b24ac=5241(84)=361 D>0  n1,2=2ab±D=25±361 n1,2=25±19 n1,2=2.5±9.5 n1=12 n2=7  n>0 n=n1=12

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