Center of line segment

Calculate the distance of the point X [1,3] from the center of the line segment x = 2-6t, y = 1-4t ; t is <0,1>.

Correct result:

d =  4.4721

Solution:

$$\begin{gathered} t=(0+1)\mathrm{/}2={\displaystyle \frac{1}{2}}=0.5 \\ {x}_0=2-6\cdot t=2-6\cdot 0.5=-1 \\ {y}_0=1-4\cdot t=1-4\cdot 0.5=-1 \\ {x}_1=1 \\ {y}_1=3 \\ d=\sqrt{(x_1-x_0{)}^2+(y_1-y_0{)}^2}=\sqrt{(1-(-1){)}^2+(3-(-1){)}^2}=2\sqrt{5}=4.4721 \end{gathered}$$

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