A car

A car weighing 1.05 tonnes driving at the maximum allowed speed in the village (50 km/h) hit a solid concrete bulkhead. Calculate height it would have to fall on the concrete surface to make the impact intensity the same as in the first case!

Correct result:

h =  9.645 m

Solution:

m=1.05 t→kg=1.05⋅ 1000 kg=1050 kg v=50 km/h→m/s=50/3.6 m/s=13.88889 m/s  g=10 m/s2  v=gt t=v/g=13.8889/10≐2518≐1.3889 s  h=12⋅ g⋅ t2=12⋅ 10⋅ 1.38892=3125324=9.645 mm=1.05 \ t \rightarrow kg=1.05 \cdot \ 1000 \ kg=1050 \ kg \ \\ v=50 \ km/h \rightarrow m/s=50 / 3.6 \ m/s=13.88889 \ m/s \ \\ \ \\ g=10 \ \text{m/s}^2 \ \\ \ \\ v=gt \ \\ t=v/g=13.8889/10 \doteq \dfrac{ 25 }{ 18 } \doteq 1.3889 \ \text{s} \ \\ \ \\ h=\dfrac{ 1 }{ 2 } \cdot \ g \cdot \ t^2=\dfrac{ 1 }{ 2 } \cdot \ 10 \cdot \ 1.3889^2=\dfrac{ 3125 }{ 324 }=9.645 \ \text{m}

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