# Symmetry by plane

Determine the coordinates of a image of point A (3, -4, -6) at a symmetry that is determined by the plane x-y-4z-13 = 0

x =  1
y =  -2
z =  2

### Step-by-step explanation:

$y=-\left(-1\right)+b=-\left(-1\right)+\left(-3\right)=-2$

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