Isosceles trapezium

Calculate the area of an isosceles trapezium ABCD if a = 10cm, b = 5cm, c = 4cm.

Correct result:

S =  28 cm2

Solution:

a=10 cm b=5 cm c=4 cm  x=(a−c)/2=(10−4)/2=3 cm h=b2−x2=52−32=4 cm  S=a+c2⋅ h=10+42⋅ 4=28 cm2

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