Solve 3

Solve quadratic equation:

(6n+1) (4n-1) = 3n2

Correct result:

n1 =  0.271
n2 =  0

Solution:

(6n+1)(4n−1)=3n2  21n2−2n−1=0  a=21;b=−2;c=−1 D=b2−4ac=22−4⋅21⋅(−1)=88 D>0  n1,2=−b±D2a=2±8842=2±22242 n1,2=0.04761905±0.22335313142 n1=0.270972179039 n2=−0.175734083801   Factored form of the equation:  21(n−0.270972179039)(n+0.175734083801)=0  n1=0.271

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