VCP equation

Solve the following equation with variations, combinations and permutations:

4 V(2,x)-3 C(2,x+ 1) - x P(2) = 0

Correct result:

x =  3


C2(4)=(42)=4!2!(42)!=4321=6 4 V(2,x)3 (2x+1)xP(2)=0 4x(x1)3(x+1)x/2x2=0  4 x (x1)3 (x+1) x/2x 2=0 2.5x27.5x=0  a=2.5;b=7.5;c=0 D=b24ac=7.5242.50=56.25 D>0  x1,2=b±D2a=7.5±56.255 x1,2=1.5±1.5 x1=3 x2=0   Factored form of the equation:  2.5(x3)x=0 x>0 x=x1=3 b=(2x+1)=(23+1)=6 y=4 3 2 1/(1)3 bx 2 1=4 3 2 1/13 63 2 1=0

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