VCP equation

Solve the following equation with variations, combinations, and permutations:

4 V(2,x)-3 C(2,x+ 1) - x P(2) = 0

Correct answer:

x =  3

Step-by-step explanation:

C2(4)=(24)=2!(42)!4!=2143=6 4 V(2,x)3 (x+ 12)  x P(2) = 0 4 x (x1)3 (x+1) x/2x 2=0  4 x (x1)3 (x+1) x/2x 2=0 2.5x27.5x=0  a=2.5;b=7.5;c=0 D=b24ac=7.5242.50=56.25 D>0  x1,2=2ab±D=57.5±56.25 x1,2=1.5±1.5 x1=3 x2=0 x>0 x=x1=3 b=(x+12)=(3+12)=6 y=4 3 2 1/(1)3 bx 2 1=4 3 2 1/13 63 2 1=0

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