# The tub

If we drop the 5 l from the first tap and the from second 2 liters of water, the water in the tub will have a temperature of 25°C. If we drop 3 l from the first tap and from second 4 l of water, the water in the tub will have a temperature of 21°C. Determine the water temperatures flowing from both taps.

Correct result:

a =  29 °C
b =  15 °C

#### Solution:

5a+2b = 25•(5+2)
3a + 4b = 21•(3+4)

5•a+2•b = 25•(5+2)
3•a + 4•b = 21•(3+4)

5a+2b = 175
3a+4b = 147

a = 29
b = 15

Calculated by our linear equations calculator.
$b=15=1{5}^{\circ }\text{C}$

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