Tanker

An oil tanker can be emptied by the first pump in 4.9 hours. Second pump can empty an tanker in 8 hours. If the first pump started at 4:00 and second 1.4 hour later, at what time will the tanker be empty?

Result

t =  3.6 h

Solution:

$\dfrac{1}{ 4.9}t + \dfrac{1}{ 8}(t-1.4) = 1 \ \\ \ \\ t = \dfrac{ 4.9\cdot 8+1.4\cdot 4.9 }{ 4.9+8 } = 3.6 \ \text{h} = 3:34$

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