Tanker

An oil tanker can be emptied by the first pump in 4.9 hours. Second pump can empty an tanker in 8 hours. If the first pump started at 4:00 and second 1.4 hour later, at what time will the tanker be empty?

Correct result:

t =  3.6 h

Solution:

$$\begin{gathered} {\displaystyle \frac{1}{4.9}}t+{\displaystyle \frac{1}{8}}(t-1.4)=1 \\ t={\displaystyle \frac{4.9\cdot 8+1.4\cdot 4.9}{4.9+8}}=3.6\text{ h}=3:34 \end{gathered}$$

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