# A speedboat

A speedboat goes 900 km against a current of 25 km/hr. Its trip took 10 minutes longer than it would have taken to travel with the current. What is the speedboat's speed in still water?

### Correct answer:

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t1+t2=T

900/(v-25)+900/(v+25)==2(900/v)+10/60

Ans. 190.09kph

note:

1. the whole trip is 2 times the time plus 10mins due to counter current. (time= 2T + 10/60). time unit is in hours.

2. (900/x) is the velocity in still waters. since Distance = V*T, thus, T=D/v.

hope it can helps.

900/(v-25)+900/(v+25)==2(900/v)+10/60

Ans. 190.09kph

note:

1. the whole trip is 2 times the time plus 10mins due to counter current. (time= 2T + 10/60). time unit is in hours.

2. (900/x) is the velocity in still waters. since Distance = V*T, thus, T=D/v.

hope it can helps.

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