Trolleybus line No. 206 measured 24 km. If the trolleybus goes faster by 5 km/h, the way there and back would is shorter by 33 minutes. Calculate the trolleybus speed and how much time it takes a return trip.

Correct answer:

Trolleybus speed is:  18.5 km/h
The return trip took:  155.4 min

Step-by-step explanation:

s=24 km 33 min=0.55 h 2s=vt 2s=(v+5)(t0.55) vt=vt+5t0.55v2.75 0=5t0.55v2.75 0=5t20.552242.75t 0=5t22.75t26.4 t1,2=b±D2a=2.75±535.5610 t1,2=0.275±2.3142223315835 t1=2.5892223315835 t2=2.0392223315835 t>0;t=t1=155.4 min  v=224t1=18.54 km/h

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