Isosceles triangle

Find the area of an isosceles triangle whose leg is twice the base, b=1

Correct answer:

A =  0.9682

Step-by-step explanation:

b=1 a=2 b=2 1=2  a2=h2+(b/2)2  h=a2(b/2)2=22(1/2)21.9365  A=2b h=21 1.9365=0.9682

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