Isosceles trapezoid

Calculate the area of an isosceles trapezoid whose bases are in the ratio of 4:3; leg b = 13 cm and height = 12 cm.

Correct result:

S =  420 cm2

Solution:

S=(a+c)h/2  a12=b2−h2 a1=b2−h2=132−122=5 cm a=c+2a1 a/c=4/3 (c+2a1)c=4/3 3(c+2a1)=4c 6a1=c c=6a1=6⋅5=30 cm a=c+2a1=30+2⋅5=40 cm  S=(a+c)h/2=(40+30)⋅12/2=420 cm2 

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