Isosceles trapezoid

Calculate the content of an isosceles trapezoid whose bases are at ratio 5:3, the arm is 6cm long and it is 4cm high.

Correct result:

S =  71.5542 cm2


a:c=5:3 b=6 cm d=b=6=6 cm h=4 cm  x=b2h2=6242=2 5 cm4.4721 cm a=x+c+x 3a=5c 3 (c+2x)=5c 3c+6x=5c 2c=6x  c=3 x=3 4.4721=6 5 cm13.4164 cm a=5/3 c=5/3 13.4164=10 5 cm22.3607 cm  S=(a+c) h/2=(22.3607+13.4164) 4/2=32 571.5542=71.5542 cm2   Verifying Solution:  k1=ac=22.360713.4164=531.6667

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