Isosceles trapezoid

Calculate the area of an isosceles trapezoid whose bases are at a ratio of 5:3. The arm is 6cm long and 4cm high.

Correct answer:

S =  71.5542 cm2

Step-by-step explanation:

a:c = 5:3 b=6 cm d=b=6 cm h=4 cm  x=b2−h2​=62−42​=2 5​ cm≐4.4721 cm a = x+c+x 3a = 5c 3⋅ (c+2x) = 5c 3c + 6x  = 5c 2c = 6x  c=3⋅ x=3⋅ 4.4721=6 5​ cm≐13.4164 cm a=5/3⋅ c=5/3⋅ 13.4164=10 5​ cm≐22.3607 cm  S=(a+c)⋅ h/2=(22.3607+13.4164)⋅ 4/2=32 5​≐71.5542 cm2   Verifying Solution:  k1​=ca​=13.416422.3607​=35​≐1.6667

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