Digit Count Numbers Sequence

How many times does the digit 7 appear in the numbers from 1 to 777?

Final Answer:

n =  234

Step-by-step explanation:

n1=1 n2=10+101=19 n3=(777700)+7 (n2+n1)3=(777700)+7 (19+1)3=214  n=n1+n2+n3=1+19+214=234



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You need to know the following knowledge to solve this word math problem:

combinatoricsbasic operations and conceptsnumbersGrade of the word problem

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