The triangle 5

The triangle below has vertices A(-1,-2), B(2,2), and C(-1,4). What is the area of △ABCin square coordinate units?

Correct answer:

S =  9

Step-by-step explanation:

A=(1,2) B=(2,2) C=(1,4)  a=dist(B,C)=BC=(BxCx)2+(ByCy)2=(2(1))2+(24)2=133.6056 b=dist(C,A)=CA=(CxAx)2+(CyAy)2=((1)(1))2+(4(2))2=6 c=dist(A,B)=AB=(AxBx)2+(AyBy)2=((1)2)2+((2)2)2=5  s=2a+b+c=23.6056+6+57.3028  S=s (sa) (sb) (sc)=7.3028 (7.30283.6056) (7.30286) (7.30285)=9

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