Three Painters School Days

One painter would paint a school by himself in 28 days. The second painter would paint the school by himself in 24 days. They also called a third painter because they needed to paint the school in 8 days. The three of them painted the school together in 8 days. In how many days would the third painter paint the school by himself?

Final Answer:

c =  21 d

Step-by-step explanation:

 8 (1/28 + 1/24+ 1/c) = 1  8 (c/28+c/24+1)=c  64c=1344  c=641344=21  c=21=21 d



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algebranumbersUnits of physical quantitiesthemes, topicsGrade of the word problem

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