Silo

Outer perimeter of silo is 32 m. Concrete wall is 35 cm thick. What is diameter and area of inside floor of silo?

Result

d =  9.49 m
S =  70.67 m2

Solution:

32=2πr=πD d=D−2h=32π−2⋅35100=9.49 m32 = 2 \pi r = \pi D \ \\ d = D - 2h = \dfrac{ 32}{ \pi } -\dfrac{ 2\cdot 35}{100} = 9.49 \ \text{m}
S=πr2=πd24=70.67 m2S = \pi r^2 = \pi \dfrac{ d^2}{4} = 70.67 \ \text{m}^2

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