The size

The sides of the trapezium are 3/4*x cm, x cm, 2*(x+1) cm and 3(x+2) cm long respectively. If its perimeter is 60cm, calculate the length of each side.

Final Answer:

a =  5.7778 cm
b =  7.7037 cm
c =  17.4074 cm
d =  29.1111 cm

Step-by-step explanation:

$$\begin{gathered} 3/4x+x+2(x+1)+3(x+2)=60 \\ 3/4\cdot x+x+2\cdot (x+1)+3\cdot (x+2)=60 \\ 27x=208 \\ x=\frac{208}{27}=7.7037037 \\ x=\frac{208}{27}\doteq 7.703704 \\ a=3/4\cdot x=3/4\cdot 7.7037=5.7778\text{cm} \end{gathered}$$

$b=x=7.7037=7.7037\text{cm}$

$c=2\cdot (x+1)=2\cdot (7.7037+1)=17.4074\text{cm}$

$d=3\cdot (x+2)=3\cdot (7.7037+2)=29.1111\text{cm}$

Try another example