600 pencils

600 pencils we want to be divided into three groups. The biggest groups have ten pens more than the smallest. How many ways can this be done?

Correct result:

n =  3

Solution:

600=a+b+(a10) 610=a+b a>b>a10 0<a 0<b  z=610/3=6103203.3333  a1=204,b1=202,c1=194 a2=205,b2=200,c2=195 a3=206,b3=198,c3=196  n=3600=a+b+(a-10) \ \\ 610=a+b \ \\ a>b>a-10 \ \\ 0<a \ \\ 0<b \ \\ \ \\ z=610/3=\dfrac{ 610 }{ 3 } \doteq 203.3333 \ \\ \ \\ a_{1}=204, b_{1}=202, c_{1}=194 \ \\ a_{2}=205, b_{2}=200, c_{2}=195 \ \\ a_{3}=206, b_{3}=198, c_{3}=196 \ \\ \ \\ n=3



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